-4.9x^2+6x+0.6=0

Solution for -4.9x^2+6x+0.6=0 equation:

-4.9x^2+6x+0.6=0

a = -4.9; b = 6; c = +0.6;
Δ = b2-4ac
Δ = 62-4·(-4.9)·0.6
Δ = 47.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{47.76}}{2*-4.9}=\frac{-6-\sqrt{47.76}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{47.76}}{2*-4.9}=\frac{-6+\sqrt{47.76}}{-9.8}
$